Little Petya loves presents. His mum bought him two strings of the same size for his birthday. The strings consist of uppercase and lowercase Latin letters. Now Petya wants to compare those two strings lexicographically. The letters' case does not matter, that is an uppercase letter is considered equivalent to the corresponding lowercase letter. Help Petya perform the comparison.
Each of the first two lines contains a bought string. The strings' lengths range from 1 to 100 inclusive. It is guaranteed that the strings are of the same length and also consist of uppercase and lowercase Latin letters.
If the first string is less than the second one, print "-1". If the second string is less than the first one, print "1". If the strings are equal, print "0". Note that the letters' case is not taken into consideration when the strings are compared.
aaaa aaaA
0
abs Abz
-1
abcdefg AbCdEfF
1
If you want more formal information about the lexicographical order (also known as the "dictionary order" or "alphabetical order"), you can visit the following site:
- http://en.wikipedia.org/wiki/Lexicographical_order
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scanner = new Scanner(System.in);
String str1 = scanner.nextLine().toLowerCase();
String str2 = scanner.nextLine().toLowerCase();
boolean flag = false;
char[] ch1 = str1.toCharArray();
char[] ch2 = str2.toCharArray();
for(int i = 0;i < ch1.length;i++){
if(ch1[i] == ch2[i]){
flag = true;
}else{
flag = false;
if(ch1[i] < ch2[i]){
System.out.println(-1);
}else{
System.out.println(1);
}
break;
}
}
if(flag){
System.out.println(0);
}
scanner.close();
}
}
本文介绍了一个简单的字符串比较问题,要求忽略大小写差异进行字典序比较。通过将输入字符串统一转换为小写形式,并逐字符对比,实现了快速有效的比较。
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