1061 1 运算符的优先级 2 打破惯性思维永远都是A到Z

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
char week[7][5] = {"MON","TUE","WED","THU","FRI","SAT","SUN"};
int main()
{
	char s1[70],s2[70],s3[70],s4[70]; 
	scanf("%s%s%s%s",s1,s2,s3,s4);
	int i = 0;
	int len1 =strlen(s1),len2=strlen(s2),len3=strlen(s3),len4=strlen(s4);
	while(i < min(len1,len2))
	{
		if(s1[i] >= 'A' && s1[i] <= 'G' && s1[i] == s2[i])
		{
			printf("%s ",week[s1[i]-'A']);
			break;
		}
		i++;
	}
	i++;
	while(i < min(len1,len2))
	{
		if(((s1[i] >= 'A' && s1[i] <= 'N' )||(s1[i] >= '0' && s1[i] <= '9'))&& s1[i] == s2[i])
		{
			
			if(s1[i] >= '0' && s1[i] <= '9')
			    printf("%02d:",s1[i] - '0');
			else printf("%d:",s1[i]-'A'+10);
			break;
		}
		i++;
	}
    int j = 0;
	while(j < min (len3,len4))
	{     
		if(((s3[j] >= 'A' && s3[j] <= 'Z' )||(s4[j] >= 'a' && s4[j] <= 'z'))&& s3[j] == s4[j])
		    {
		    	printf("%02d",j);break;
		    } 
		j++;
	}
	
	
	return 0;
}