poj 3349 Snowflake Snow Snowflakes

最新推荐文章于 2019-10-31 22:07:42 发布

原创最新推荐文章于 2019-10-31 22:07:42 发布 · 271 阅读

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本文深入探讨了AI在音视频处理领域的应用，包括视频分割、语义识别、自动驾驶、AR、SLAM等前沿技术，以及AI在音视频处理过程中的作用与实践。

题意：一共n组数，每组有六个数，查询在n组数列里有没有（包含的数字相同，并且数字顺序符合，可以是顺序也可以是逆序，也可以是从任意一个数开始的顺序）

Description

You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your program will read information about a collection of snowflakes, and search for a pair that may be identical. Each snowflake has six arms. For each snowflake, your program will be provided with a measurement of the length of each of the six arms. Any pair of snowflakes which have the same lengths of corresponding arms should be flagged by your program as possibly identical.

Input

The first line of input will contain a single integer n, 0 < n ≤ 100000, the number of snowflakes to follow. This will be followed byn lines, each describing a snowflake. Each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow ake. The lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. For example, the same snowflake could be described as 1 2 3 4 5 6 or 4 3 2 1 6 5.

Output

If all of the snowflakes are distinct, your program should print the message:
No two snowflakes are alike.
If there is a pair of possibly identical snow akes, your program should print the message:
Twin snowflakes found.

Sample Input

2
1 2 3 4 5 6
4 3 2 1 6 5

Sample Output

Twin snowflakes found.

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <queue>
#include <stack>
#define LL long long
#define INF 0x3f3f3f3f
#define Mod 100007
//#pragma comment(linker,"STACK:1024000,1024000")
using namespace std;

struct node
{
    int a[6];
    node *next;
}*p,*q;

struct Point
{
    int num;
    node *next;
} Head[Mod];

bool cmp(node *a,node *b)
{
    for(int i=0; i<6; i++)
        if((a->a[0] == b->a[i] && a->a[1] == b->a[(i+1)%6] && a->a[2] == b->a[(i+2)%6] && a->a[3] == b->a[(i+3)%6] && a->a[4] == b->a[(i+4)%6] && a->a[5] == b->a[(i+5)%6]) || (a->a[0] == b->a[i] && a->a[1] == b->a[(i+5)%6] && a->a[2] == b->a[(i+4)%6] && a->a[3] == b->a[(i+3)%6] && a->a[4] == b->a[(i+2)%6] && a->a[5] == b->a[(i+1)%6]) )
            return true;
    return false;
}

int main()
{
    //freopen("in.txt","r",stdin);
    int n;
    while(~scanf("%d",&n))
    {
        for(int i=0; i<Mod; i++)
        {
            Head[i].num = 0;
            Head[i].next = NULL;
        }
        for(int i=0; i<n; i++)
        {
            p = new node;
            p->next = NULL;
            int sum = 0;
            for(int j=0; j<6; j++)
            {
                scanf("%d",&p->a[j]);
                sum = (sum + p->a[j])%Mod;
            }
            Head[sum].num ++;
            p->next = Head[sum].next;
            Head[sum].next = p;
        }
        bool flag = false;
        for(int i=0; i<Mod; i++)
        {
            if(Head[i].num <= 1)
                continue;
            p = Head[i].next;
            while(p)
            {
                q = p->next;
                while(q)
                {
                    if(cmp(q,p))
                    {
                        flag = true;
                        break;
                    }
                    if(flag)
                        break;
                    q = q->next;
                }
                if(flag)
                    break;
                p = p->next;
            }
        }

        if(flag)
            printf("Twin snowflakes found.\n");
        else
            printf("No two snowflakes are alike.\n");
    }
    return 0;
}