建立一个简单的登录系统:
1.本人下载的是Stuts 1.2.9 ,解压后将lib下的jar包拷贝到web-inf / lib下,包括以下几个:

2.在web-inf下建立struts-config.xml文件,代码如下:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE struts-config PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 1.2//EN"
"http://jakarta.apache.org/struts/dtds/struts-config_1_2.dtd">
<struts-config>
</struts-config>3.修改web.xml文件:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<init-param>
<param-name>debug</param-name>
<param-value>2</param-value>
</init-param>
<init-param>
<param-name>detail</param-name>
<param-value>2</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>

<!-- Standard Action Servlet Mapping -->
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
</web-app>
4.创建用户登录界面login.jsp(action=login.do),login_success.jsp,login_error.jsp:

<%...@ page language="java" import="java.util.*" pageEncoding="GB18030"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body>
<H1>登录页面</H1>
<HR>
<form action="login.do">
用户名称:<input type="text" name="username"><br>
用户密码:<input type="password" name="password"><br>
<HR>
<input type="submit" name="btn_login" value="登录"><br>
</form>
</body>
</html>

<%...@ page language="java" contentType="text/html; charset=GB18030"
pageEncoding="GB18030"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=GB18030">
<title>Insert title here</title>
</head>
<body>
<H1>登录成功</H1>
</body>
</html>

<%...@ page language="java" contentType="text/html; charset=GB18030"
pageEncoding="GB18030"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=GB18030">
<title>Insert title here</title>
</head>
<body>
<H1>登录失败</H1>
</body>
</html>5.创建LoginActionForm.java集成ActionForm,注意该类的成员属性名称应与form表单中的一致,并且要生成相应的getter and setter,封装好:
package com.ycringfinger.struts;
import org.apache.struts.action.ActionForm;

public class LoginActionForm extends ActionForm ...{
private String username;
private String password;

public String getUsername() ...{
return username;
}
public void setUsername(String username) ...{
this.username = username;
}
public String getPassword() ...{
return password;
}
public void setPassword(String password) ...{
this.password = password;
}
}
6.创建LoginAction.java继承自Action,并要重写其execute方法,在这里我让该方法接收表单数据并判断用户名及密码,如成功则跳转到login_success.jsp,若抛出Exception,则跳转至login_error.jsp:
package com.ycringfinger.struts;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;

public class LoginAction extends Action ...{

public ActionForward execute(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception ...{
LoginActionForm laf = (LoginActionForm) form;
String username = laf.getUsername();
String password = laf.getPassword();
try ...{
UserManager.getInstance().validate(username, password);
return mapping.findForward("success");
} catch (UserNotFoundException e) ...{
e.printStackTrace();
} catch (PasswordNotCorrectException e) ...{
e.printStackTrace();
}
return mapping.findForward("error");
}
} 
7.配置stuts-config.xml,注意<action path="/login" type="com.ycringfinger.struts.LoginAction" name="loginActionForm" scope="request">中/login 对应了form中的action=login.do,name="loginActionForm"则对应了form-bean中的loginActionForm,至于scope你则可以根据实际情况选择。
<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE struts-config PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 1.2//EN"
"http://jakarta.apache.org/struts/dtds/struts-config_1_2.dtd">
<struts-config>
<form-beans>
<form-bean name="loginActionForm" type="com.ycringfinger.struts.LoginActionForm"></form-bean>
</form-beans>
<action-mappings>
<action path="/login" type="com.ycringfinger.struts.LoginAction" name="loginActionForm" scope="request">
<forward name="success" path="/login_success.jsp"></forward>
<forward name="error" path="/login_error.jsp"></forward>
</action>
</action-mappings>
</struts-config>

8.大功告成,测试。
本文介绍如何使用Struts 1.2.9搭建一个简单的登录系统。从环境配置到各组件实现进行了详细说明,包括struts-config.xml和web.xml配置、JSP页面设计、ActionForm与Action类编写。
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