PAT甲级1001. A+B Format (20)

最新推荐文章于 2025-03-05 20:47:12 发布

原创最新推荐文章于 2025-03-05 20:47:12 发布 · 257 阅读

0 ·

CC 4.0 BY-SA版权

PAT甲级专栏收录该内容

2 篇文章

订阅专栏

本文介绍了一个简单的C++程序，该程序接收两个整数输入，计算它们的和，并以标准格式输出结果，其中涉及如何正确使用逗号分隔千位数的方法。

题目：

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

#include<cstdio>
using namespace std;
int main() {
    int a, b, c, d[5], i, flag=1, num=0;
    scanf ("%d %d", &a, &b);
    c = a + b;
    if (c < 0) {
        flag = -1;
        c = -c;
    }
    if (c == 0)
        printf ("0");
    while (c != 0) {
        d[num++] = c % 1000;
        c /= 1000;
    }
    if (flag == -1)
        printf ("-");
    if (num > 0)
        printf ("%d", d[num-1]);
    for (i=num-2; i>=0; i--)
        printf (",%03d", d[i]);
    return 0;
}