选择程序结构作业

原创已于 2025-10-03 12:03:02 修改 · 185 阅读

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#算法 #数据结构 #c语言 #c++

于 2025-10-03 11:59:32 首次发布

C语言练习小Demo，仅供参考

Demo 1.三数找中值

#include<stdio.h>

int main (){
	int a,b,c;
	int max,min,second;
	scanf("%d",&a);
	scanf("%d",&b);
	scanf("%d",&c);
	max=a>b ? a:b;
	max=max>c ? max:c;
	min=a<b ? a:b;
	min=min<c ? min:c;
	
	second=a+b+c-max-min;
	printf("%d\n", second);
	
	
	return 0;
}

Demo 2.整除判断

#include <stdio.h>

int main() {
	int num;
	scanf("%d", &num);
	if (num % 5 == 0 && num % 11 == 0) {
		printf("Y\n");
	} else {
		printf("N\n");
	}
	return 0;
}

Demo 3.闰年判断

#include <stdio.h>

int main() {
	int year;
	scanf("%d", &year);
	if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
		printf("Y\n");
	} else {
		printf("N\n");
	}
	return 0;
}

Demo 4.二次方程求实根个数

Demo 5.组成三角形

#include <stdio.h>

int main() {
	float a, b, c;
	scanf("%f %f %f", &a, &b, &c);
	
	if (a + b > c && a + c > b && b + c > a) {
		printf("Y\n");
	} else {
		printf("N\n");
	}
	
	return 0;
}

Demo 6.该交电费了

#include <stdio.h>

int main() {
	double electricity;
	double cost = 0;
	scanf("%lf", &electricity);
	
	if (electricity <= 50) {
		cost = electricity * 0.5;
	} else if (electricity <= 100) {
		cost = 50 * 0.5 + (electricity - 50) * 0.6;
	} else if (electricity <= 200) {
		cost = 50 * 0.5 + 50 * 0.6 + (electricity - 100) * 0.8;
	} else {
		cost = 50 * 0.5 + 50 * 0.6 + 100 * 0.8 + (electricity - 200) * 1.0;
	}
	
	printf("%.2f\n", cost);
	return 0;
}

Demo 7.百货公司促销

#include <stdio.h>

int main() {
	double price, discount, pay;

	while (scanf("%lf", &price) != EOF) {
	
		if (price >= 5000) {
			discount = 0.8;
		} else if (price >= 3000) {
			discount = 0.85;
		} else if (price >= 2000) {
			discount = 0.9;
		} else if (price >= 1000) {
			discount = 0.95;
		} else {
			discount = 1.0;
		}
		
		pay = price * discount;
	
		printf("discount=%.2f,pay=%.2f\n", discount, pay);
	}
	return 0;
}

Demo 8.简单的计算器

#include <stdio.h>

int main() {
	int a, b, result;
	char op;
	
	// 读取输入的表达式，格式为"a op b"
	scanf("%d%c%d", &a, &op, &b);
	
	// 根据运算符进行相应计算
	switch(op) {
	case '+':
		result = a + b;
		break;
	case '-':
		result = a - b;
		break;
	case '*':
		result = a * b;
		break;
	case '/':
		result = a / b;  
		break;
	default:
	
		result = 0;
		break;
	}
	

	printf("%d%c%d=%d\n", a, op, b, result);
	
	return 0;
}

Demo 9.小吴等电梯

#include <stdio.h>

int main() {
	long long n;  
	scanf("%lld", &n);
	long long batches = (n + 12) / 12;	
	long long time;
	if (batches == 0) {
	
		time = 2;
	} else {
	
		time = (batches - 1) * 4 + 2;
	}
	
	printf("%lld\n", time);
	return 0;
}

Demo 10.卡特兹函数

#include <stdio.h>

int main() {
	int n, k;
	scanf("%d", &n);
	
	
	if (n % 2 == 1) {
		k = 3 * n + 1;
	} else {
		k = n / 2;
	}
	
	printf("%d", k);
	return 0;
}