1001. A+B Format_jmap -dump format=b-优快云博客

本文介绍了一个简单的C++程序，该程序接收两个整数作为输入，并返回它们的和，同时将结果格式化为每三位数字用逗号分隔的形式。文章提供了完整的代码实现，并解释了如何将数字转换为字符串以便于进行格式处理。

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Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

题目大意：

给出a和b，计算a+b并按照格式从后往前数每三位一个逗号的格式输出。

思路：

把数字转换成字符串处理。

AC代码：

#include <iostream>
#include <iomanip>
#include <stdio.h>
#include <stdlib.h>
#include <cmath>
#include <algorithm>
#include <cstring>
#include <cctype>
#include <sstream>
#include <map>
#include <set>
#include <vector>
#include <queue>
#include <stack>
using namespace std;

int main()
{
    int a,b,c,i,len;
    string num;
    stringstream ss;
    cin>>a>>b;
    c = a+b;
    if(c < 0)
    {
        cout<<"-";
        c = abs(c);
    }
    ss<<c;
    ss>>num;
    len = num.size();
    for(i=0;i<len;i++)
    {
        if((len-i)%3==0 && i!=0)
            cout<<",";
        cout<<num[i];
    }
    cout<<endl;
	return 0;
}