#pragma warning(disable:4786)
#include <string>
#include <map>
#include <iostream>
using namespace std;
int main()
{
map<char,int> m;
m['0'] = 0;
m['1'] = 1;
m['2'] = 2;
m['3'] = 3;
m['4'] = 4;
m['5'] = 5;
m['6'] = 6;
m['7'] = 7;
m['8'] = 8;
m['9'] = 9;
/*上面的10条赋值语句可采用下面循环来简化
for (int j=0; j <10; j++)
#include <string>
#include <map>
#include <iostream>
using namespace std;
int main()
{
map<char,int> m;
m['0'] = 0;
m['1'] = 1;
m['2'] = 2;
m['3'] = 3;
m['4'] = 4;
m['5'] = 5;
m['6'] = 6;
m['7'] = 7;
m['8'] = 8;
m['9'] = 9;
/*上面的10条赋值语句可采用下面循环来简化
for (int j=0; j <10; j++)

这段代码演示了如何使用C++中的map数据结构将字符串表示的数字逐位拆分并求和。通过创建一个映射关系,将字符'0'到'9'映射为整数值,然后遍历字符串计算总和。
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