LeetCode 27. Remove Element

最新推荐文章于 2025-08-31 17:43:57 发布

原创最新推荐文章于 2025-08-31 17:43:57 发布 · 285 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#leetcode

算法专栏收录该内容

30 篇文章

订阅专栏

本文介绍了一种在不使用额外空间的情况下从数组中移除指定值的方法，并保持了常数级别的内存消耗。通过一个简单的C++实现示例，展示了如何高效地完成这一任务。

Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

Example:
Given input array nums = [3,2,2,3], val = 3

Your function should return length = 2, with the first two elements of nums being 2.

class Solution {
public:
    int removeElement(vector<int>& nums, int val) {
        int count=0;
        for(int i=0;i<nums.size();i++){
            if(nums[i]==val){
                count++;
            }
            else{
                nums[i-count] = nums[i];
            }
        }
        return nums.size()-count;
    }
};