leetcode 237. Delete Node in a Linked List 解法 python

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#leetcode #链表 #删除 #算法

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本文介绍了一种在单链表中删除除尾部以外任意节点的方法，通过修改目标节点的值和指向下一个节点的指针，实现在原地删除节点的功能。文章提供了具体的解题思路和代码实现。

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一.问题描述

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:

Example 1:

Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.

Example 2:

Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.

Note:

The linked list will have at least two elements.
All of the nodes' values will be unique.
The given node will not be the tail and it will always be a valid node of the linked list.
Do not return anything from your function.

二.解题思路

这道题要求in-place的方案，就是在值本身上面改，

又是在函数里面, 所以不能直接 node=node.next，

只能改node里面的值，

分别赋值node.val 和 node.next

更多leetcode算法题解法: 专栏 leetcode算法从零到结束

三.源码

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:



 

Example 1:

Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:

Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
 

Note:

The linked list will have at least two elements.
All of the nodes' values will be unique.
The given node will not be the tail and it will always be a valid node of the linked list.
Do not return anything from your function.