Python高级编程-如何快速找到多个字典中的公工键（key）

最新推荐文章于 2022-10-25 14:45:00 发布

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1.第一种方案（一般的）
>>> from random import randint ,sample
>>> sample ('abcdefgh',4)
['g', 'b', 'c', 'd']
>>> sample ('abcdefgh',randint (4,7))
['h', 'e', 'a', 'c', 'b', 'f']
>>> {x:randint (1,4)for x in sample ('abcdefgh',randint (4,7)) }
{'d': 1, 'e': 4, 'h': 2, 'g': 4, 'b': 2, 'a': 2, 'f': 2}
>>> s1={x:randint (1,4)for x in sample ('abcdefgh',randint (4,7)) }
>>> s1
{'g': 4, 'd': 4, 'c': 4, 'f': 1, 'a': 4}
>>> s2={x:randint (1,4)for x in sample ('abcdefgh',randint (4,7)) }
>>> s3={x:randint (1,4)for x in sample ('abcdefgh',randint (4,7)) }
>>> s4={x:randint (1,4)for x in sample ('abcdefgh',randint (4,7)) }
>>> s1
{'g': 4, 'd': 4, 'c': 4, 'f': 1, 'a': 4}
>>> s2
{'b': 4, 'f': 2, 'e': 1, 'g': 3, 'h': 3}
>>> s3
{'e': 3, 'g': 2, 'h': 2, 'a': 3, 'f': 2}
>>> s4
{'h': 2, 'g': 2, 'e': 4, 'b': 1}
>>> for k in s1:
    if k in s2 and k in s3 and k in s4:
        res.append(k)
        
Traceback (most recent call last):
  File "<pyshell#60>", line 3, in <module>
    res.append(k)
NameError: name 'res' is not defined
>>> res=[]
>>> res
[]
>>> for k in s1:
    if k in s2 and k in s3 and k in s4:
        res.append(k)
        
>>>
>>> res
['g']
>>>