#include <iostream>
#include<cmath>
using namespace std;
int F[510000] = { 1,1,2 };
int fun(int n, int m) {
for (int i = 3; i <= m; i++) {
F[i] = 1 << (i - 1);
}
for (int i = 3; i <= n; i++) {
if (i <= m) {
continue;
}
F[i] = 2 * F[i - 1] - F[i - m - 1];
}
return F[n]%10007;
}
int main()
{
int n,m;
cin >> n>>m;
if (m == 1)
cout<<1%10007;
else
cout << fun(n, m);
return 0;
}
注:商汤笔试题,只能通过50%。
参考:
https://88250.b3log.org/steps-problem.html