PAT 1001 A+B Format

最新推荐文章于 2025-03-05 20:47:12 发布

原创最新推荐文章于 2025-03-05 20:47:12 发布 · 684 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#PAT #甲级

ACM__日常刷题专栏收录该内容

31 篇文章

订阅专栏

博客围绕PAT 1001 A+B Format题目展开，给出时间和内存限制，描述问题为计算a+b并按标准格式输出结果，即每三位用逗号分隔。还给出输入输出要求、示例及题目网址，最后提及代码。

PAT 1001 A+B Format
Time Limit : 400 ms
Memory Limit : 64 MB

Problem Description
Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input
Each input file contains one test case. Each case contains a pair of integers a and b where −10⁶≤a,b≤10⁶. The numbers are separated by a space.

Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

题目网址：https://pintia.cn/problem-sets/994805342720868352/problems/994805528788582400

代码

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
    int a,b,c;
    int sum[1000];
    while (~scanf("%d %d",&a,&b))
    {
        c = a+b;
        int t,k=0;
        if (c<1000&&c>-1000)
        {
            cout<<c<<endl;
            continue;
        }
        while (1)
        {
            t = c%1000;
            c = c/1000;
            if (t<0&&c!=0)
                t = -t;
            sum[k++] = t;
            if (c==0)
                break;
        }
        printf("%d,", sum[k-1]);
        for (int i=k-2;i>0;i--)
            printf("%03d,", sum[i]);
        printf("%03d\n", sum[0]);
    }
    return 0;
}