原题链接:https://leetcode.com/problems/diameter-of-binary-tree/
1. Description
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
2. Solution
For a node, the diameter of this node is left subtree’s depth plus right subtree’s depth.
Therefore we can use dfs to count every node’s depth and find the longest diameter.
code
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
int ans = 0;
public int diameterOfBinaryTree(TreeNode root) {
dfs(root);
return ans;
}
public int dfs(TreeNode t ){
if(t == null){
return 0;
}
int l = dfs(t.left);
int r = dfs(t.right);
ans = Math.max(ans, l +r);
return Math.max(l, r) +1;
}
}