package jiao.er;
import java.util.Scanner;
public class Shangpin {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int book = 12;
int qianbi = 1;
int xiangpi = 2;
int kele = 3;
int lingshi = 5;
System.out.println("书本的价格为:"+book+"元,一共有20元");
System.out.println("1.铅笔的价格为:"+qianbi+"元");
System.out.println("2.橡皮的价格为:"+xiangpi+"元");
System.out.println("3.可乐的价格为:"+kele+"元");
System.out.println("4.零食的价格为:"+lingshi+"元");
System.out.println("请输入要买的商品序号:");
int id = sc.nextInt();
switch (id){
case 1:
int qianbimo = 20-book;
int a1 = qianbimo/qianbi;
int b1 = qianbimo%qianbi;
System.out.println("买完书还可以买铅笔"+a1+"个,还剩"+b1+"元");
break;
case 2:
int xiangpimo = 20-book;
int a2 = xiangpimo/xiangpi;
int b2 = xiangpimo%xiangpi;
System.out.println("买完书还可以买橡皮"+a2+"个,还剩"+b2+"元");
break;
case 3:
int kelemo = 20-book;
int a3 = kelemo/kele;
int b3 = kelemo%kele;
System.out.println("买完书还可以买可乐"+a3+"个,还剩"+b3+"元");
break;
case 4:
int lingshimo = 20-book;
int a4 = lingshimo/lingshi;
int b4 = lingshimo%lingshi;
System.out.println("买完书还可以买橡皮"+a4+"个,还剩"+b4+"元");
break;
default:
System.out.println("序号有误");
break;
}
}
}
编写一个智能购物计算小程序,在一家商店有书本、铅笔、橡皮、可乐、零食五种商品,假如你带了20元,且必须购买一本书,剩余的钱还可以购买哪种商品,可以购买几件,购买完后又能剩余多少钱?
于 2023-11-01 16:57:58 首次发布