mysql> select s1.*,(select count(0) + 1 from score s2 where s2.score > s1.score)rank from score s1;

https://blog.youkuaiyun.com/jslcylcy/article/details/72627762
mysql> select s1.*,(select count(0) + 1 from score s2 where s2.score > s1.score)rank from score s1;

https://blog.youkuaiyun.com/jslcylcy/article/details/72627762
1304
495
2310

被折叠的 条评论
为什么被折叠?