查询oeacle耗时最长的SQL

1.查看总消耗时间最多的前10条SQL语句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
last_load_time,
v.PARSING_USER_ID,
ROUND(v.ELAPSED_TIME / 1000000 / (CASE
WHEN (EXECUTIONS = 0 OR NVL(EXECUTIONS, 1 ) = 1) THEN
1
ELSE
EXECUTIONS
END),
2) “执行时间’S’”,
v.SQL_FULLTEXT,
v.cpu_time,
v.disk_reads,
rank() over(order by v.elapsed_time desc) elapsed_rank
from v$sql v ) a
where elapsed_rank <= 100 and last_load_time > to_char(sysdate - 1/24, ‘YYYY-MM-DD/HH:MI:SS’) order by “执行时间’S’” desc

查询最近一小时内最慢的SQL:

select executions, cpu_time/1e6 as cpu_sec, elapsed_time/1e6 as elapsed_sec, round(elapsed_time/sqrt(executions)) as important, v.*
from v$sql v
where executions > 10 and last_load_time > to_char(sysdate - 1/24, ‘YYYY-MM-DD/HH:MI:SS’)
order by important desc

2.查看CPU消耗时间最多的前10条SQL语句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
v.elapsed_time,
v.cpu_time,
v.disk_reads,
rank() over(order by v.cpu_time desc) elapsed_rank
from v$sql v) a
where elapsed_rank <= 10;

3.查看消耗磁盘读取最多的前10条SQL语句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
v.elapsed_time,
v.cpu_time,
v.disk_reads,
rank() over(order by v.disk_reads desc) elapsed_rank
from v$sql v) a
where elapsed_rank <= 10;

一、查询执行最慢的sql
select *
from(selectsa.SQL_TEXT,
sa.SQL_FULLTEXT,
sa.EXECUTIONS"执行次数",
round(sa.ELAPSED_TIME / 1000000, 2)“总执行时间”,
round(sa.ELAPSED_TIME / 1000000 / sa.EXECUTIONS, 2)“平均执行时间”,
sa.COMMAND_TYPE,
sa.PARSING_USER_ID"用户ID",
u.username"用户名",
sa.HASH_VALUE
fromv$sqlareasaleftjoinal{l}_{u}sersuonsa.PARSIN{G}_{U}SE{R}_{I}D=u.use{r}_{i}dwheresa.EXECUTIONS>0orderby(sa.ELAPSE{D}_{T}IME/sa.EXECUTIONS)desc)whererownum<=50;二、查询次数最多的sqlselect\ast from(selects.SQ{L}_{T}EXT,s.EXECUTIONS"执行次数",s.PARSIN{G}_{U}SE{R}_{I}D"用户名",rank()over(orderbyEXECUTIONSdesc)EXE{C}_{R}ANKfromv$sql s
leftjoinall_users u
onu.USER_ID = s.PARSING_USER_ID) t
whereexec_rank <= 100;
转载：https://blog.youkuaiyun.com/xwnxwn/article/details/78062433?utm_source=app&app_version=4.5.0