程序员面试金典——11.2变位词排序

程序员面试金典——11.2变位词排序

Solution1:
参考网址：https://www.nowcoder.com/profile/845063/codeBookDetail?submissionId=12676002
知识点：利用set中count函数的功能，查找是否存在某个值

class SortString {
public:
    vector<string> sortStrings(vector<string> str, int n) {
        // write code here
        sort(str.begin(), str.end());
        vector<string> res;
        set<string> str_set;
        for(int i = 0; i < str.size(); i++) {
            string temp = str[i];
            sort(temp.begin(), temp.end());
            if(str_set.count(temp) == 0) {
                str_set.insert(temp);
                res.push_back(str[i]);
            }
        }
        return res;
    }
};