题目
法1:DP
Python
class Solution:
def rob(self, nums: List[int]) -> int:
n = len(nums)
dp = [0] * n
dp[0] = nums[0]
for i in range(1, n):
if i == 1:
dp[i] = max(nums[0], nums[1])
else:
dp[i] = max(dp[i-2] + nums[i], dp[i-1])
return dp[n-1]
Java
class Solution {
public int rob(int[] nums) {
int n = nums.length;
if (n == 1) {
return nums[0];
}
if (n == 2) {
return Math.max(nums[0], nums[1]);
}
int pre0 = nums[0], pre1 = Math.max(nums[0], nums[1]), max = 0;
for (int i = 2; i < n; ++i) {
max = Math.max(pre0 + nums[i], pre1);
pre0 = pre1;
pre1 = max;
}
return max;
}
}