/**
- 检测是否有emoji表情
- @param source
- @return
*/
public static boolean containsEmoji(String source) {
int len = source.length();
for (int i = 0; i < len; i++) {
char codePoint = source.charAt(i);
if (!isEmojiCharacter(codePoint)) { // 如果不能匹配,则该字符是Emoji表情
return true;
}
}
return false;
}
/**
- 判断是否是Emoji
- @param codePoint
-
比较的单个字符 - @return
*/
private static boolean isEmojiCharacter(char codePoint) {
return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)
|| (codePoint == 0xD)
|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))
|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD))
|| ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));
}
//完美解决输入框中不能输入的非法字符
InputFilter inputFilter=new InputFilter() {
Pattern pattern = Pattern.compile("[^a-zA-Z0-9\\u4E00-\\u9FA5_,.?!:;…~_\\-\"\"/@*+'()<>{}/[/]()<>{}\\[\\]=%&$|\\/♀♂#¥£¢€\"^` ,。?!:;……~“”、“()”、(——)‘’@‘·’&*#《》¥《〈〉》〈$〉[]£[]{}{}¢【】【】%〖〗〖〗/〔〕〔〕\『』『』^「」「」|﹁﹂`.]");
@Override
public CharSequence filter(CharSequence charSequence, int i, int i1, Spanned spanned, int i2, int i3) {
Matcher matcher= pattern.matcher(charSequence);
if(!matcher.find()){
return null;
}else{
Toast.makeText(MyApplication.context, "非法字符!", Toast.LENGTH_SHORT).show();
return "";
}
}
};
//调用
EditText et = (EditText) view.findViewById(R.id.et);
et.setFilters(new InputFilter[]{inputFilter});
这篇博客介绍了一个Java方法,用于检测字符串中是否包含emoji表情,并提供了一个InputFilter的实现,以防止输入框中输入非法字符,尤其是emoji。
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