Secret Research ——字符串

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本文解析了特定实验室中秘密研究的加密实验结果，包括正、负、失败和未完成实验的编码方式，并提供了一个简单的程序来解密给定的数字序列。

Secret Research

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result', `negative result', `experiment failed' or `experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:

 positive result 		 S = 1 or S = 4 or S = 78  negative result 		 S = S35  experiment failed 		 S = 9S4  experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output

For each analysed sequence of digits the following lines should be sent to output (in separate lines):

+ for a positive result - for a negative result * for a failed experiment ? for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input

Sample Output

+
-
?
*

读了大半天题目，到最后竟然是个水题！！！！

本题目一共四种输出情况，+，-，*，？，分别有他们对应的数字，只要一一对应起来就好了，不过要注意先判断‘-’再判断‘？’。

#include <iostream>
#include <stdio.h>
#include <string.h>

using namespace std;

int main()
{
    int n,l;
    char sz[10000];
    scanf("%d",&n);
    while(n--)
    {
        scanf("%s",sz);
        l = strlen(sz);
        if(strcmp(sz,"1") == 0 || strcmp(sz,"4") == 0 || strcmp(sz,"78") == 0)
            printf("+\n");
        else if(sz[l-1] == '5' && sz[l-2] == '3')
            printf("-\n");
        else if(sz[0] == '9' && sz[l-1] == '4')
            printf("*\n");
        else if(sz[0] == '1' && sz[1] == '9' && sz[2] == '0')
            printf("?\n");
    }
    return 0;
}