NSSCTF Round#16 Basic——nc_pwnre

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于 2024-01-26 12:00:19 发布 · 380 阅读

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本文介绍了解一道网络安全竞赛中的题目，涉及nc连接、XOR加密、十六进制转Base64的解密过程，最终揭示出NSSCTF比赛的flag。

题目描述：

一道简单的nc题！！！来点pwn_re震撼~

node4.anna.nssctf.cn:28868

nc连接一下，发现提示"xor"，并给出一串十六进制字符

0x44,0x7c,0x5e,0x44,0x41,0x21,0x42,0x57,0x75,0x21,0x74,0x56,0x44,0x57,0x5d,0x67,0x44,0x46,0x29,0x45,0x5d,0x56,0x29,0x67,0x46,0x22,0x25,0x76,0x74,0x6a,0x52,0x69,0x5d,0x47,0x41,0x78,0x76,0x41,0x2d,0x2d

enc=[0x44, 0x7c, 0x5e, 0x44, 0x41, 0x21, 0x42, 0x57, 0x75, 0x21, 0x74, 0x56, 0x44, 0x57, 0x5d, 0x67, 0x44, 0x46, 0x29, 0x45, 0x5d, 0x56, 0x29, 0x67, 0x46, 0x22, 0x25, 0x76, 0x74, 0x6a, 0x52, 0x69, 0x5d, 0x47, 0x41, 0x78, 0x76, 0x41, 0x2d, 0x2d]
for i in range(len(enc)):
      print(chr(enc[i]^16),end="")

用脚本异或一下，得到一串base64密文TlNTQ1RGe1dFTGMwTV9UMF9wV25fdzByMW