Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree [3,9,20,null,null,15,7]
,
3
/ \
9 20
/ \
15 7
return its bottom-up level order traversal as:
[
[15,7],
[9,20],
[3]
]
<思路>记录一层的节点,存储这层节点的val,用BFS继续遍历下一层节点。
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def levelOrderBottom(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if root is None:
return []
level = [root] #store nodes for each level
final = [[root.val]] #append vals
while level:
val=[] #store val for each level
queue=[]
for node in level:
if node.left:
queue.append(node.left)
if node.right:
queue.append(node.right)
for node in queue:
val.append(node.val)
if val:
final.append(val)
level = queue
return final[::-1]