1000 Sum Problem

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#c++

本文详细解析了HDOJ平台上的经典求和问题，通过示例输入输出，介绍了如何使用C++实现求和算法。该算法适用于计算从1到n的整数之和，且结果在32位带符号整数范围内。

Sum Problem

Time Limit : 1000/500ms (Java/Other) Memory Limit : 65536/32768K (Java/Other)

Total Submission(s) : 24 Accepted Submission(s) : 15

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + … + n.

Input

The input will consist of a series of integers n, one integer per line.

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

Sample Input

1
100

Sample Output

5050

#include<iostream>
#include<cmath>
#include<iomanip>

using namespace std;

int main(void)
{
	double n;
	double sum = 0;

	while (cin >> n)
	{
		sum = 0;
		for (double i = 1; i <= n; i++)
		{
			sum += i;
		}
		cout << fixed << setprecision(0) << sum << endl << endl;
	}
	return 0;
}