find a subarray that contains the largest sum, constraint that sum is less than k

Given an array of integers A and an integer k, find a subarray that contains the largest sum, subject to a constraint that the sum is less than k?


摘自

https://www.quora.com/Given-an-array-of-integers-A-and-an-integer-k-find-a-subarray-that-contains-the-largest-sum-subject-to-a-constraint-that-the-sum-is-less-than-k




You can do this in  O(nlog(n)) 


First thing to note is that sum of subarray  (i,j]  is just the sum of the first  j  elements less the sum of the first  i  elements. Store these cumulative sums in the array cum. Then the problem reduces to finding   i,j  such that  i<j  and  cum[j]-cum[i]  is as close to  k  but lower than it.


To solve this, scan from left to right. Put the  cum[i]  values that you have encountered till now into a set. When you are processing  cum[j]  what you need to retrieve from the set is the smallest number in the set such which is bigger than  cum[j]-k . This lookup can be done in  O(log n)  using upper_bound. Hence the overall complexity is  O(nlog(n)) .


Here is a c++ function that does the job, assuming that K>0 and that the empty interval with sum zero is a valid answer. The code can be tweaked easily to take care of more general cases and to return the interval itself.


int best_cumulative_sum(int ar[],int N,int K)
{
set<int> cumset;
cumset.insert(0);
int best=0,cum=0;
for(int i=0;i<N;i++)
{
cum+=ar[i];
set<int>::iterator sit=cumset.upper_bound(cum-K);
if(sit!=cumset.end())best=max(best,cum-*sit);
cumset.insert(cum);
}
return best;
}


内容概要:本文详细介绍了CCF-GESP认证的学习资源与知识点指南,分为官方资源与平台、知识点学习与解析、备考策略与工具、实战项目与进阶资源以及学习工具推荐五个部分。官方资源包括CCF数字图书馆提供的免费真题库、一站式学习平台和GESP官网的最新真题下载及考试环境说明。知识点学习部分涵盖Python、C++和图形化编程(Scratch)的核心内容与实战案例。备考策略方面,提出了基础、强化和冲刺三个阶段的分阶段计划,并强调了在线题库模拟测试与社区交流的重要性。实战项目与进阶资源则为不同编程语言提供了具体的应用场景,如Python的智能客服机器人和C++的并行编程与嵌入式开发。最后,推荐了多种学习工具,如代码编辑器VS Code、模拟考试平台和社区支持渠道。 适合人群:准备参加CCF-GESP认证考试的考生,特别是对Python、C++或Scratch编程语言有兴趣的学习者。 使用场景及目标:①帮助考生系统化地学习官方资源,熟悉考试形式和内容;②通过分阶段的备考策略,提高应试能力和编程技能;③利用实战项目和进阶资源,增强实际编程经验和解决复杂问题的能力。 阅读建议:建议考生按照文章中的分阶段备考策略逐步推进学习进度,充分利用官方提供的资源进行练习和模拟测试,并积极参与社区交流以获取更多备考经验和疑难解答。
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值