[LeetCode53]Merge Sorted Array

Given two sorted integer arrays A and B, merge B into A as one sorted array.

Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn respectively.

Analysis:

The classic problem. (can be found in the book "Cracking the Code Interview").
Part of the merge sort, merge the arrays from the back by comparing the elements.

Java

public void merge(int A[], int m, int B[], int n) {
        int count = m+n-1;
        m--;n--;
        while(m>=0 && n>=0){
        	A[count--] = A[m]>B[n]? A[m--]:B[n--];
        }
        while(n>=0)
        	A[count--] = B[n--];
    }

c++

void merge(int A[], int m, int B[], int n) {
        int count = m+n-1;
        m--;n--;
        while(m>=0 && n>=0){
        	A[count--] = A[m]>B[n]? A[m--]:B[n--];
        }
        while(n>=0)
        	A[count--] = B[n--];
    }



评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值