Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn respectively.
The classic problem. (can be found in the book "Cracking the Code Interview").
Part of the merge sort, merge the arrays from the back by comparing the elements.
Java
public void merge(int A[], int m, int B[], int n) {
int count = m+n-1;
m--;n--;
while(m>=0 && n>=0){
A[count--] = A[m]>B[n]? A[m--]:B[n--];
}
while(n>=0)
A[count--] = B[n--];
}
c++
void merge(int A[], int m, int B[], int n) {
int count = m+n-1;
m--;n--;
while(m>=0 && n>=0){
A[count--] = A[m]>B[n]? A[m--]:B[n--];
}
while(n>=0)
A[count--] = B[n--];
}