内连接:
查询出来的每一项为 object[]数组,左表存在object[0]中,右表存在object[1]中,object[0]和object[1]的关联关系有没有设置,取决于你的配置文件中,关联的配置时候lazy的值,如果lazy=false,则马上维护关系,lazy=true,先不维护关系,等用到关联关系维系的值时才查询。
Session session = DBUtil.getSession();
String hql = "from Deptment d inner join d.employees";
Query query = session.createQuery(hql);
//如果设置lazy=”false",这时候就会关联部门和员工,除了发送内连接语句外,还发送了查询每个
//部门下有哪些员工的sql语句
List list = query.list();
Iterator iter = list.iterator();
while(iter.hasNext())
{
Object[] object = (Object[]) iter.next();
System.out.println("部门信息:");
System.out.println(object[0]);
Deptment dept = (Deptment)object[0];
//如果设置lazy="true"的时候,这时候才去查询部门的员工,发sql语句
System.out.println(dept.getEmployees());
System.out.println("员工信息:");
System.out.println(object[1]);
}
session.close();
结果1(设置关联关系的维护为lazy=true):
Hibernate:
select
deptment0_.deptid as deptid0_0_,
employees1_.epno as epno1_1_,
deptment0_.deptname as deptname0_0_,
employees1_.deptid as deptid1_1_,
employees1_.epname as epname1_1_
from
deptment deptment0_
inner join
employee employees1_
on deptment0_.deptid=employees1_.deptid
部门信息:
Deptment [deptid=1, deptname=aaa]
Hibernate:
select
employees0_.deptid as deptid1_,
employees0_.epno as epno1_,
employees0_.epno as epno1_0_,
employees0_.deptid as deptid1_0_,
employees0_.epname as epname1_0_
from
employee employees0_
where
employees0_.deptid=?
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
员工信息:
Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]
部门信息:
Deptment [deptid=1, deptname=aaa]
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
员工信息:
Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
Hibernate:
select
employees0_.deptid as deptid1_,
employees0_.epno as epno1_,
employees0_.epno as epno1_0_,
employees0_.deptid as deptid1_0_,
employees0_.epname as epname1_0_
from
employee employees0_
where
employees0_.deptid=?
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
员工信息:
Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
员工信息:
Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]
结果2(设置关联关系的维护lazy=false,关联关系立马维护,产生多条sql语句)
Hibernate:
select
deptment0_.deptid as deptid0_0_,
employees1_.epno as epno1_1_,
deptment0_.deptname as deptname0_0_,
employees1_.deptid as deptid1_1_,
employees1_.epname as epname1_1_
from
deptment deptment0_
inner join
employee employees1_
on deptment0_.deptid=employees1_.deptid
Hibernate:
select
employees0_.deptid as deptid1_,
employees0_.epno as epno1_,
employees0_.epno as epno1_0_,
employees0_.deptid as deptid1_0_,
employees0_.epname as epname1_0_
from
employee employees0_
where
employees0_.deptid=?
Hibernate:
select
employees0_.deptid as deptid1_,
employees0_.epno as epno1_,
employees0_.epno as epno1_0_,
employees0_.deptid as deptid1_0_,
employees0_.epname as epname1_0_
from
employee employees0_
where
employees0_.deptid=?
部门信息:
Deptment [deptid=1, deptname=aaa]
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
员工信息:
Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]
部门信息:
Deptment [deptid=1, deptname=aaa]
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
员工信息:
Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
员工信息:
Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
员工信息:
Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]
迫切内连接(不管设置lazy=true或者lazy=false,他关联关系立马就维护好了,且只发送一条sql语句,且结果集中的每条结果为 对象(本例中为部门对象,部门里面的员工已经填充好了)
Session session = DBUtil.getSession();
String hql = "from Deptment d inner join fetch d.employees";
Query query = session.createQuery(hql);
List list = query.list();
Iterator iter = list.iterator();
while(iter.hasNext())
{
Deptment object = (Deptment) iter.next();
System.out.println("部门信息:");
System.out.println(object);
System.out.println("员工信息:");
System.out.println(object.getEmployees());
}
结果:
Hibernate:
select
deptment0_.deptid as deptid0_0_,
employees1_.epno as epno1_1_,
deptment0_.deptname as deptname0_0_,
employees1_.deptid as deptid1_1_,
employees1_.epname as epname1_1_,
employees1_.deptid as deptid0__,
employees1_.epno as epno0__
from
deptment deptment0_
inner join
employee employees1_
on deptment0_.deptid=employees1_.deptid
部门信息:
Deptment [deptid=1, deptname=aaa]
员工信息:
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
部门信息:
Deptment [deptid=1, deptname=aaa]
员工信息:
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
员工信息:
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
员工信息:
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
左外连接:在内连接的基础上,保证左表的数据不能丢失,如果左表中没有对应的右表数据,则右表对象置为空。lazy的设置导致的结果影响和内连接相同。
代码:
Session session = DBUtil.getSession();
String hql = "from Deptment d left join d.employees";
Query query = session.createQuery(hql);
List list = query.list();
Iterator iter = list.iterator();
while(iter.hasNext())
{
Object[] object = (Object[]) iter.next();
System.out.println("部门信息:");
System.out.println(object[0]);
System.out.println("员工信息:");
if(object[1]!=null){
System.out.println(object[1]);
}else{
System.out.println("null");
}
}
session.close();
结果(lazy=true 的时候),我们可以看到最后多了一个null:
Hibernate:
select
deptment0_.deptid as deptid0_0_,
employees1_.epno as epno1_1_,
deptment0_.deptname as deptname0_0_,
employees1_.deptid as deptid1_1_,
employees1_.epname as epname1_1_
from
deptment deptment0_
left outer join
employee employees1_
on deptment0_.deptid=employees1_.deptid
部门信息:
Deptment [deptid=1, deptname=aaa]
员工信息:
Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]
部门信息:
Deptment [deptid=1, deptname=aaa]
员工信息:
Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
员工信息:
Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
员工信息:
Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]
部门信息:
Deptment [deptid=2, deptname=aaa]
员工信息:
null
迫切左外连接:
Session session = DBUtil.getSession();
String hql = "from Deptment d left join fetch d.employees";
Query query = session.createQuery(hql);
List list = query.list();
Iterator iter = list.iterator();
while(iter.hasNext())
{
Deptment object = (Deptment) iter.next();
System.out.println("部门信息:");
System.out.println(object);
System.out.println("员工信息:");
System.out.println(object.getEmployees());
}
结果:
Hibernate:
select
deptment0_.deptid as deptid0_0_,
employees1_.epno as epno1_1_,
deptment0_.deptname as deptname0_0_,
employees1_.deptid as deptid1_1_,
employees1_.epname as epname1_1_,
employees1_.deptid as deptid0__,
employees1_.epno as epno0__
from
deptment deptment0_
left outer join
employee employees1_
on deptment0_.deptid=employees1_.deptid
部门信息:
Deptment [deptid=1, deptname=aaa]
员工信息:
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
部门信息:
Deptment [deptid=1, deptname=aaa]
员工信息:
[Employee [epno=2, deptment=Deptment [deptid=1, deptname=aaa], epname=shizhan2], Employee [epno=1, deptment=Deptment [deptid=1, deptname=aaa], epname=null]]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
员工信息:
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
部门信息:
Deptment [deptid=3, deptname=sdsdzz]
员工信息:
[Employee [epno=3, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=xsxs], Employee [epno=4, deptment=Deptment [deptid=3, deptname=sdsdzz], epname=ttt]]
部门信息:
Deptment [deptid=2, deptname=aaa]
员工信息:
[]